If a ball is thrown upward from the ground with an initial velocity of 48 feet per second, its height after $t$ seconds is given by the function $h(t)=-16 t^{2}+48 t$. Find the number of seconds before the ball lands on the ground.
A) 24 seconds
B) 3 seconds
C) 1.5 seconds
D) 32 seconds

Question

Quizplus · Accepted Answer

The ball lands on the ground when $h(t) = 0$. Solving the equation $-16t^2 + 48t = 0$ for $t$, we factor out $16t$, getting $16t(-t + 3) = 0$. This gives us $t = 0$ (when the ball is thrown) and $t = 3$ seconds (when the ball lands). Therefore, the correct answer is 3 seconds.

If a Ball Is Thrown Upward from the Ground with an Initial