For the given quadratic equation, one of its solutions has been provided. Use it to find the other solution.
-$40 \mathrm{x}^{2}-92 \mathrm{x}-20=0, \mathrm{x}=\frac{5}{2}$
A) $x=\frac{1}{5}$
B) $x=5$
C) $x=-\frac{5}{2}$
D) $x=-\frac{1}{5}$

Question

Quizplus · Accepted Answer

Using Vieta's formulas, the sum of the roots of the quadratic equation $ax^2 + bx + c = 0$ is $-b/a$. For the given equation, the sum of the roots is $92/40 = 2.3$. Given one root is $5/2 = 2.5$, the other root must be $2.3 - 2.5 = -0.2$, which is $-1/5$.

For the Given Quadratic Equation, One of Its Solutions Has 40x2−92x−20=0,x=5240 \mathrm{x}^{2}-92 \mathrm{x}-20=0, \mathrm{x}=\frac{5}{2}40x2−92x−20=0,x=25​

For the Given Quadratic Equation, One of Its Solutions Has $40 \mathrm{x}^{2}-92 \mathrm{x}-20=0, \mathrm{x}=\frac{5}{2}$