Factor completely. If the polynomial cannot be factored, write "prime."
-$21 x^{3}-91 x^{2}-70 x$
A) $\left(x^{2}-5\right)(21 x+14)$
B) $7 x(3 x+2)(x-5)$
C) $x(3 x+2)(7 x-35)$
D) $7(3 x-2)(x+5)$

Question

Quizplus · Accepted Answer

First, factor out the greatest common factor (GCF), which is $7x$, resulting in $7x(3x^2-13x-10)$. Then, factor the quadratic expression to get $7x(3x+2)(x-5)$.

Factor Completely 21x3−91x2−70x21 x^{3}-91 x^{2}-70 x21x3−91x2−70x A) (x2−5)(21x+14)\left(x^{2}-5\right)(21 x+14)(x2−5)(21x+14) B) 7x(3x+2)(x−5)7 x(3 x+2)(x-5)7x(3x+2)(x−5)

Factor Completely $21 x^{3}-91 x^{2}-70 x$ A) $\left(x^{2}-5\right)(21 x+14)$ B) $7 x(3 x+2)(x-5)$