Factor completely. If the polynomial cannot be factored, write "prime."
-$2 x^{2}+23 x+63$
A) $(2 x-56)(x+7)$
B) $(2 x+9)(x+7)$
C) $(x+9)(x+7)$
D) $(x-56)(x+7)$

Name: Factor completely. If the polynomial cannot be factored, write "prime." -$2 x^{2}+23 x+63$ A) $(2 x-56)(x+7)$ B) $(2 x+9)(x+7)$ C) $(x+9)(x+7)$ D) $(x-56)(x+7)$
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Question

Quizplus · Accepted Answer

The correct factorization of $2x^2 + 23x + 63$ is $(2x + 9)(x + 7)$, which multiplies out to $2x^2 + 14x + 9x + 63$, simplifying to $2x^2 + 23x + 63$.

Factor Completely 2x2+23x+632 x^{2}+23 x+632x2+23x+63 A) (2x−56)(x+7)(2 x-56)(x+7)(2x−56)(x+7) B) (2x+9)(x+7)(2 x+9)(x+7)(2x+9)(x+7) C) (x+9)(x+7)(x+9)(x+7)(x+9)(x+7) D) (x−56)(x+7)(x-56)(x+7)(x−56)(x+7)

Factor Completely $2 x^{2}+23 x+63$ A) $(2 x-56)(x+7)$ B) $(2 x+9)(x+7)$ C) $(x+9)(x+7)$ D) $(x-56)(x+7)$