Factor completely. If the polynomial cannot be factored, write "prime."
-$5 x^{5}+35 x^{4}+60 x^{3}$
A) $5 x^{3}\left(x^{2}+7 x+12\right)$
B) $x^{3}(x+3)(5 x+20)$
C) $5 x^{3}(x+3)(x+4)$
D) $x^{3}(5 x+15)(x+4)$

Question

Quizplus · Accepted Answer

The polynomial can be factored by first taking out the greatest common factor, which is $5x^3$, leaving us with $5x^3(x^2 + 7x + 12)$. The quadratic expression can be further factored into $(x+3)(x+4)$, resulting in $5x^3(x+3)(x+4)$.

Factor Completely 5x5+35x4+60x35 x^{5}+35 x^{4}+60 x^{3}5x5+35x4+60x3 A) 5x3(x2+7x+12)5 x^{3}\left(x^{2}+7 x+12\right)5x3(x2+7x+12) B) x3(x+3)(5x+20)x^{3}(x+3)(5 x+20)x3(x+3)(5x+20)

Factor Completely $5 x^{5}+35 x^{4}+60 x^{3}$ A) $5 x^{3}\left(x^{2}+7 x+12\right)$ B) $x^{3}(x+3)(5 x+20)$