Factor completely. If the polynomial cannot be factored, write "prime."
-$x^{2}+23 x-24$
A) $(x+24)(x-1)$
B) $(x-6)(x+4)$
C) $(x+6)(x-4)$
D) Prime

Question

Quizplus · Accepted Answer

The correct factorization is found by looking for two numbers that multiply to -24 (the constant term) and add to 23 (the coefficient of the middle term). Those numbers are 24 and -1, making the factorization $(x+24)(x-1)$.

Factor Completely x2+23x−24x^{2}+23 x-24x2+23x−24 A) (x+24)(x−1)(x+24)(x-1)(x+24)(x−1) B) (x−6)(x+4)(x-6)(x+4)(x−6)(x+4) C) (x+6)(x−4)(x+6)(x-4)(x+6)(x−4) D) Prime

Factor Completely $x^{2}+23 x-24$ A) $(x+24)(x-1)$ B) $(x-6)(x+4)$ C) $(x+6)(x-4)$ D) Prime