Factor completely. If the polynomial cannot be factored, write "prime."
-$x^{2}+5 x+4$
A) $(x+1)(x+4)$
B) $(x+4)(x-1)$
C) $(x+4)(x+5)$
D) $(x-1)(x-4)$

Name: Factor completely. If the polynomial cannot be factored, write "prime." -$x^{2}+5 x+4$ A) $(x+1)(x+4)$ B) $(x+4)(x-1)$ C) $(x+4)(x+5)$ D) $(x-1)(x-4)$
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Question

Quizplus · Accepted Answer

The correct factorization of $x^{2}+5x+4$ is obtained by finding two numbers that multiply to 4 and add to 5, which are 1 and 4. Thus, the polynomial factors as $(x+1)(x+4)$.

Factor Completely x2+5x+4x^{2}+5 x+4x2+5x+4 A) (x+1)(x+4)(x+1)(x+4)(x+1)(x+4) B) (x+4)(x−1)(x+4)(x-1)(x+4)(x−1) C) (x+4)(x+5)(x+4)(x+5)(x+4)(x+5) D) (x−1)(x−4)(x-1)(x-4)(x−1)(x−4)

Factor Completely $x^{2}+5 x+4$ A) $(x+1)(x+4)$ B) $(x+4)(x-1)$ C) $(x+4)(x+5)$ D) $(x-1)(x-4)$