Factor by grouping.
-$x^{2}+9 x+x+9$
A) $(x+9)(x+1)$
B) $(x-9)(x-1)$
C) $(x-9)(x+1)$
D) $(x+9)(x-1)$

Name: Factor by grouping. -$x^{2}+9 x+x+9$ A) $(x+9)(x+1)$ B) $(x-9)(x-1)$ C) $(x-9)(x+1)$ D) $(x+9)(x-1)$
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Question

Quizplus · Accepted Answer

First, rearrange the expression as $x^2 + x + 9x + 9$. Then, factor by grouping: $x(x + 1) + 9(x + 1)$. Finally, factor out the common factor $(x + 1)$, resulting in $(x + 9)(x + 1)$.

Factor by Grouping x2+9x+x+9x^{2}+9 x+x+9x2+9x+x+9 A) (x+9)(x+1)(x+9)(x+1)(x+9)(x+1) B) (x−9)(x−1)(x-9)(x-1)(x−9)(x−1) C) (x−9)(x+1)(x-9)(x+1)(x−9)(x+1) D) (x+9)(x−1)(x+9)(x-1)(x+9)(x−1)

Factor by Grouping $x^{2}+9 x+x+9$ A) $(x+9)(x+1)$ B) $(x-9)(x-1)$ C) $(x-9)(x+1)$ D) $(x+9)(x-1)$