Divide. Assume all variables are nonzero
-$\frac{40 x^{4}-35 x^{3}-40 x^{2}-35 x}{5 x}$

A) $8 x^{3}+7 x^{2}-8 x-7$
B) $8 x^{3}-7 x^{2}+8 x-7$
C) $8 x^{3}-7 x^{2}-8 x+7$
D) $8 x^{3}-7 x^{2}-8 x-7$

Question

Divide. Assume all variables are nonzero
-$\frac{40 x^{4}-35 x^{3}-40 x^{2}-35 x}{5 x}$

A) $8 x^{3}+7 x^{2}-8 x-7$
B) $8 x^{3}-7 x^{2}+8 x-7$
C) $8 x^{3}-7 x^{2}-8 x+7$
D) $8 x^{3}-7 x^{2}-8 x-7$

Quizplus · Accepted Answer

To divide the given expression by $5x$, each term in the numerator is divided by $5x$ individually. This results in:- $40x^4 / 5x = 8x^3$- $-35x^3 / 5x = -7x^2$- $-40x^2 / 5x = -8x$- $-35x / 5x = -7$Thus, the simplified expression is $8x^3 - 7x^2 - 8x - 7$, which matches option D.

Divide Assume All Variables Are Nonzero - 40x4−35x3−40x2−35x5x\frac{40 x^{4}-35 x^{3}-40 x^{2}-35 x}{5 x}5x40x4−35x3−40x2−35x​

Divide Assume All Variables Are Nonzero
- $\frac{40 x^{4}-35 x^{3}-40 x^{2}-35 x}{5 x}$