Find the missing factor or exponent(s).
-$\left(-3 a ? a^{3} ?\right)^{3}=-27 a^{18} b^{12}$
A) 4,6
B) 6,4
C) 9,7
D) 7,9

Question

Quizplus · Accepted Answer

The given expression can be simplified by recognizing that the cube of -3 is -27, and the cube of $a^x$ where $x$ is the missing exponent, multiplied by $a^3$ should equal $a^{18}$. Similarly, the missing exponent for $b$ must be such that when cubed, it equals $b^{12}$. Thus, the correct missing exponents are 6 for $a$ (since $3 + 6 = 9$ and $9 \times 3 = 27$, which matches the exponent of $a$ in the result) and 4 for $b$ (since $4 \times 3 = 12$, matching the exponent of $b$ in the result).

Find the Missing Factor or Exponent(s) (−3a?a3?)3=−27a18b12\left(-3 a ? a^{3} ?\right)^{3}=-27 a^{18} b^{12}(−3a?a3?)3=−27a18b12

Find the Missing Factor or Exponent(s) $\left(-3 a ? a^{3} ?\right)^{3}=-27 a^{18} b^{12}$