In Joe's wallet there are only $\$ 1$ bills, $\$ 5$ bills, and $\$ 10$ bills. There are 44 bills in his wallet and their total value is $\$ 219$. There are 9 more $\$ 1$ bills than $\$ 5$ bills. How many $\$ 10$ bills are in his wallet?
A) 15
B) 19
C) 16
D) 10

Question

Quizplus · Accepted Answer

The system of equations derived from the problem is: $x + y + z = 44$, $x + 5y + 10z = 219$, and $x = y + 9$, where $x$, $y$, and $z$ represent the number of \$1, \$5, and \$10 bills, respectively. Solving these equations gives $z = 15$, which means there are 15 \$10 bills in the wallet.

In Joe's Wallet There Are Only $1\$ 1$1 Bills $5\$ 5$5 Bills, And

In Joe's Wallet There Are Only $\$ 1$ Bills $\$ 5$ Bills, And