The perimeter of a rectangle is $78 \mathrm{~m}$. If the width were doubled and the length were increased by $25 \mathrm{~m}$, then the perimeter would be $158 \mathrm{~m}$. What are the dimensions?
A) Width: $15 \mathrm{~m}$; length: $24 \mathrm{~m}$
B) Width: $19 \mathrm{~m}$; length: $19 \mathrm{~m}$
C) Width: $14 \mathrm{~m}$; length: $19 \mathrm{~m}$
D) Width: $24 \mathrm{~m}$; length: $15 \mathrm{~m}$

Question

Quizplus · Accepted Answer

The original perimeter is $2l + 2w = 78$. After changes, the new perimeter is $2(l + 25) + 4w = 158$. Solving these equations, we find width $w = 15 \mathrm{~m}$ and length $l = 24 \mathrm{~m}$.

The Perimeter of a Rectangle Is 78 m78 \mathrm{~m}78 m If the Width Were Doubled and the Length Were

The Perimeter of a Rectangle Is $78 \mathrm{~m}$ If the Width Were Doubled and the Length Were