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Question 349
A) f(x) =∣x∣+1f(x) =|x|+1f(x) =∣x∣+1 B) f(x) =∣x−1∣f(x) =|x-1|f(x) =∣x−1∣ C) f(x) =∣x+1∣f(x) =|x+1|f(x) =∣x+1∣ D) f(x) =∣x∣−1f(x) =|x|-1f(x) =∣x∣−1
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