Find the slope-intercept form of the equation of a line parallel or perpendicular to the given line and passing through the given point.
-Perpendicular to $8 x+3 y=-41$, through $(-7,10)$
A) $y=\frac{8}{3} x+\frac{101}{3}$

B) $y=-\frac{3}{8} x-\frac{41}{8}$

C) $y=\frac{3}{8} x+\frac{101}{8}$

D) $y=-\frac{3}{8} x-\frac{101}{8}$

Question

Find the slope-intercept form of the equation of a line parallel or perpendicular to the given line and passing through the given point.
-Perpendicular to $8 x+3 y=-41$, through $(-7,10)$
A) $y=\frac{8}{3} x+\frac{101}{3}$

B) $y=-\frac{3}{8} x-\frac{41}{8}$

C) $y=\frac{3}{8} x+\frac{101}{8}$

D) $y=-\frac{3}{8} x-\frac{101}{8}$

Quizplus · Accepted Answer

The slope of the given line $8x + 3y = -41$ is $-\frac{8}{3}$. A line perpendicular to this will have a slope that is the negative reciprocal, which is $\frac{3}{8}$. Using the point-slope form with point $(-7, 10)$, the equation becomes $y - 10 = \frac{3}{8}(x + 7)$, which simplifies to $y = \frac{3}{8}x + \frac{101}{8}$.

Find the Slope-Intercept Form of the Equation of a Line 8x+3y=−418 x+3 y=-418x+3y=−41

Find the Slope-Intercept Form of the Equation of a Line $8 x+3 y=-41$