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-One Approximation for Euler's Number E Is the Infinite $1+\sum_{\mathrm{i}=1}^{\infty} \frac{1}{\mathrm{i} !}=1+$

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-One approximation for Euler's number e is the infinite sum $1+\sum_{\mathrm{i}=1}^{\infty} \frac{1}{\mathrm{i} !}=1+$ $\left.\left(\frac{1}{1}+\frac{1}{1 \cdot 2}+\frac{1}{1 \cdot 2 \cdot 3}+\frac{1}{1 \cdot 2 \cdot 3 \cdot 4}+\ldots\right) .\right)$ The expression $\mathrm{i}$ ! is called $\mathrm{i}$ factorial and is equal to the product of the integers from 1 through $i$ . Find the sum through $i=9$ , rounded to the nearest thousandth.

A) 2.717
B) 2.718
C) 2.708
D) 2.709