In order for a chemical reaction to remain stable, its Celsius temperature must be no more than $79.29^{\circ} \mathrm{C}$. Find the Fahrenheit temperatures at which the reaction will remain stable. $\left(\mathrm{F}=\frac{9}{5} \mathrm{C}+32\right)$ Round your answer to the nearest hundredth of a degree.
A) $\mathrm{F} \geq 174.72^{\circ}$
B) $\mathrm{F} \leq 174.72^{\circ}$
C) $\mathrm{F} \leq 26.27^{\circ}$
D) $\mathrm{F} \geq 26.27^{\circ}$

Question

Quizplus · Accepted Answer

To find the Fahrenheit temperature at which the reaction will remain stable, use the conversion formula $F = \frac{9}{5}C + 32$. Substituting $79.29^{\circ}C$ into the formula gives $F = \frac{9}{5} \times 79.29 + 32 = 174.722$, which rounds to $174.72^{\circ}F$. Therefore, the reaction will remain stable at Fahrenheit temperatures less than or equal to $174.72^{\circ}F$.

In Order for a Chemical Reaction to Remain Stable, Its 79.29∘C79.29^{\circ} \mathrm{C}79.29∘C

In Order for a Chemical Reaction to Remain Stable, Its $79.29^{\circ} \mathrm{C}$