Sheila notes that if $\mathrm{a}=20$ and $\mathrm{b}=20$, then $\mathrm{a}-\mathrm{b}=\mathrm{b}-\mathrm{a}=0$. She concludes that for any real numbers $\mathrm{a}$ and $\mathrm{b}, \mathrm{a}-\mathrm{b}=\mathrm{b}-\mathrm{a}$. Do you agree with her reasoning? If not, why not?

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The Answer of Sheila notes that if $\mathrm{a}=20$ and $\mathrm{b}=20$, then $\mathrm{a}-\mathrm{b}=\mathrm{b}-\mathrm{a}=0$. She concludes that for any real numbers $\mathrm{a}$ and $\mathrm{b}, \mathrm{a}-\mathrm{b}=\mathrm{b}-\mathrm{a}$. Do you agree with her reasoning? If not, why not?

Sheila Notes That If a=20\mathrm{a}=20a=20 And b=20\mathrm{b}=20b=20 , Then a−b=b−a=0\mathrm{a}-\mathrm{b}=\mathrm{b}-\mathrm{a}=0a−b=b−a=0 She Concludes That for Any Real Numbers

Sheila Notes That If $\mathrm{a}=20$ And $\mathrm{b}=20$ , Then $\mathrm{a}-\mathrm{b}=\mathrm{b}-\mathrm{a}=0$ She Concludes That for Any Real Numbers