Simplify .
-$\frac{17}{18}-\frac{2}{3} \cdot \frac{3}{5}$

A) $\frac{1}{6}$

B) $\frac{1}{162}$

C) $\frac{49}{90}$

D) $1 \frac{41}{49}$

Question

Simplify .
-$\frac{17}{18}-\frac{2}{3} \cdot \frac{3}{5}$

A) $\frac{1}{6}$

B) $\frac{1}{162}$

C) $\frac{49}{90}$

D) $1 \frac{41}{49}$

Quizplus · Accepted Answer

First, perform the multiplication: $\frac{2}{3} \cdot \frac{3}{5} = \frac{2 \cdot 3}{3 \cdot 5} = \frac{2}{5}$. Then, subtract this result from $\frac{17}{18}$: $\frac{17}{18} - \frac{2}{5} = \frac{17 \cdot 5}{18 \cdot 5} - \frac{2 \cdot 18}{5 \cdot 18} = \frac{85}{90} - \frac{36}{90} = \frac{49}{90}$.

Simplify - 1718−23⋅35\frac{17}{18}-\frac{2}{3} \cdot \frac{3}{5}1817​−32​⋅53​ A) 16\frac{1}{6}61​ B) 1162\frac{1}{162}1621​ C) 4990\frac{49}{90}9049​ D) 141491 \frac{41}{49}14941​

Simplify
- $\frac{17}{18}-\frac{2}{3} \cdot \frac{3}{5}$ A) $\frac{1}{6}$ B) $\frac{1}{162}$ C) $\frac{49}{90}$ D) $1 \frac{41}{49}$