Solve the problem.
-If an object is dropped, the distance it falls during $t$ seconds is given by $\mathrm{d}(\mathrm{t})=\frac{1}{2} \mathrm{gt}^{2}$, where $\mathrm{g}$ is about $32 \mathrm{ft} / \mathrm{sec}^{2}$. Find the distance an object would fall in 8 seconds.
A) $2048 \mathrm{ft}$
B) $1024 \mathrm{ft}$
C) $512 \mathrm{ft}$
D) $128 \mathrm{ft}$

Question

Quizplus · Accepted Answer

To find the distance an object would fall in 8 seconds, substitute $t = 8$ and $g = 32 \mathrm{ft/sec}^2$ into the formula: $\mathrm{d}(t) = \frac{1}{2}gt^2$. This gives $\mathrm{d}(8) = \frac{1}{2} \times 32 \times 8^2 = 1024 \mathrm{ft}$.

Solve the Problem ttt Seconds Is Given By d(t)=12gt2\mathrm{d}(\mathrm{t})=\frac{1}{2} \mathrm{gt}^{2}d(t)=21​gt2 , Where g\mathrm{g}g

Solve the Problem $t$ Seconds Is Given By $\mathrm{d}(\mathrm{t})=\frac{1}{2} \mathrm{gt}^{2}$ , Where $\mathrm{g}$