Find the $x$-intercepts.
-$y=-3 x^{2}-2 x+2$

A) $\left(\frac{-1+\sqrt{7}}{3}, 0\right)$ and $\left(\frac{-1-\sqrt{7}}{3}, 0\right)$

B) No x-intercepts

C) $\left(\frac{-1+2 \sqrt{7}}{3}, 0\right)$ and $\left(\frac{-1-2 \sqrt{7}}{3}, 0\right)$

D) $\left(\frac{1+\sqrt{7}}{3}, 0\right)$ and $\left(\frac{1-\sqrt{7}}{3}, 0\right)$

Question

Find the $x$-intercepts.
-$y=-3 x^{2}-2 x+2$

A) $\left(\frac{-1+\sqrt{7}}{3}, 0\right)$ and $\left(\frac{-1-\sqrt{7}}{3}, 0\right)$

B) No x-intercepts

C) $\left(\frac{-1+2 \sqrt{7}}{3}, 0\right)$ and $\left(\frac{-1-2 \sqrt{7}}{3}, 0\right)$

D) $\left(\frac{1+\sqrt{7}}{3}, 0\right)$ and $\left(\frac{1-\sqrt{7}}{3}, 0\right)$

Quizplus · Accepted Answer

To find the $x$-intercepts, set $y=0$ and solve the quadratic equation $0=-3x^2-2x+2$. Using the quadratic formula, $x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}$, where $a=-3$, $b=-2$, and $c=2$, we find $x=\frac{-(-2)\pm\sqrt{(-2)^2-4(-3)(2)}}{2(-3)}$, which simplifies to $x=\frac{2\pm\sqrt{4+24}}{-6}=\frac{2\pm\sqrt{28}}{-6}=\frac{2\pm2\sqrt{7}}{-6}=\frac{-1\pm\sqrt{7}}{3}$.

Find The xxx -Intercepts y=−3x2−2x+2y=-3 x^{2}-2 x+2y=−3x2−2x+2 A) (−1+73,0)\left(\frac{-1+\sqrt{7}}{3}, 0\right)(3−1+7​​,0) And (−1−73,0)\left(\frac{-1-\sqrt{7}}{3}, 0\right)(3−1−7​​,0) B) No X-Intercepts C)

Find The $x$ -Intercepts $y=-3 x^{2}-2 x+2$ A) $\left(\frac{-1+\sqrt{7}}{3}, 0\right)$ And $\left(\frac{-1-\sqrt{7}}{3}, 0\right)$ B) No X-Intercepts

C)