Simplify.
-$\sqrt{\frac{98 \mathrm{r}^{2}}{\mathrm{x}^{4}}}$
A) $\frac{49 r \sqrt{2}}{x^{2}}$
B) $\frac{r \sqrt{98}}{x^{2}}$
C) $\frac{7 \sqrt{2 r^{2}}}{x^{2}}$
D) $\frac{7 r \sqrt{2}}{x^{2}}$

Question

Quizplus · Accepted Answer

First, simplify under the square root: $98 = 49 \times 2$ and $r^2$ remains as is. Since $49 = 7^2$, it can be taken out of the square root as $7$, and $r^2$ as $r$, leaving $\sqrt{2}$ under the square root. Thus, the simplified form is $\frac{7r\sqrt{2}}{x^2}$.

Simplify - 98r2x4\sqrt{\frac{98 \mathrm{r}^{2}}{\mathrm{x}^{4}}}x498r2​​ A) 49r2x2\frac{49 r \sqrt{2}}{x^{2}}x249r2​​ B) r98x2\frac{r \sqrt{98}}{x^{2}}x2r98​​ C) 72r2x2\frac{7 \sqrt{2 r^{2}}}{x^{2}}x272r2​​

Simplify
- $\sqrt{\frac{98 \mathrm{r}^{2}}{\mathrm{x}^{4}}}$ A) $\frac{49 r \sqrt{2}}{x^{2}}$ B) $\frac{r \sqrt{98}}{x^{2}}$ C) $\frac{7 \sqrt{2 r^{2}}}{x^{2}}$