Solve the problem.
-An airplane took $5 \mathrm{hr}$ to fly $600 \mathrm{mi}$ against a head wind. The return trip with the same wind took 1 $\mathrm{hr}$. Find the speed of the plane in still air.
A) $240 \mathrm{mph}$
B) $360 \mathrm{mph}$
C) $120 \mathrm{mph}$
D) $600 \mathrm{mph}$

Question

Quizplus · Accepted Answer

The speed of the plane in still air can be found by averaging the speeds for both directions. Going against the wind, the speed was $600 \, \text{mi} / 5 \, \text{hr} = 120 \, \text{mph}$. Returning with the wind, the speed was $600 \, \text{mi} / 1 \, \text{hr} = 600 \, \text{mph}$. The average speed, which represents the speed in still air, is $(120 + 600) / 2 = 360 \, \text{mph}$.

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