Solve the problem.
-Joe has a collection of nickels and dimes that is worth $\$ 4.45$. If the number of dimes were doubled and the number of nickels were increased by 15 , the value of the coins would be $\$ 7.30$. How many dimes does he have?
A) 15 dimes
B) 21 dimes
C) 10 dimes
D) 47 dimes

Question

Quizplus · Accepted Answer

Let the number of nickels be $n$ and the number of dimes be $d$. The value of the nickels and dimes can be represented as $0.05n + 0.10d = 4.45$. If the number of dimes is doubled and the number of nickels is increased by 15, the new value is $0.05(n + 15) + 0.10(2d) = 7.30$. Solving these equations simultaneously gives $d = 21$, so Joe has 21 dimes.

Solve the Problem $4.45\$ 4.45$4.45 If the Number of Dimes Were Doubled and the Dimes

Solve the Problem $\$ 4.45$ If the Number of Dimes Were Doubled and the Dimes