Solve the problem.
-The perimeter of a rectangle is $58 \mathrm{~cm}$. One side is $11 \mathrm{~cm}$ longer than the other side. Find the lengths of the sides.
A) $18 \mathrm{~cm}, 29 \mathrm{~cm}$
B) $9 \mathrm{~cm}, 20 \mathrm{~cm}$
C) $9 \mathrm{~cm}, 11 \mathrm{~cm}$
D) $10 \mathrm{~cm}, 21 \mathrm{~cm}$

Question

Quizplus · Accepted Answer

The perimeter of a rectangle is given by $2l + 2w = 58$, where $l$ is the length and $w$ is the width. Given one side is $11 \mathrm{~cm}$ longer than the other, we can set $l = w + 11$. Substituting and solving the equations, we find $w = 9 \mathrm{~cm}$ and $l = 20 \mathrm{~cm}$.

Solve the Problem 58 cm58 \mathrm{~cm}58 cm One Side Is 11 cm11 \mathrm{~cm}11 cm Longer Than the Other Side

Solve the Problem $58 \mathrm{~cm}$ One Side Is $11 \mathrm{~cm}$ Longer Than the Other Side