Solve the problem.
-If an object is thrown upward with an initial velocity of $16 \mathrm{ft} / \mathrm{sec}$, its height after $\mathrm{t}$ sec is given by $\mathrm{h}=16 \mathrm{t}-16 \mathrm{t}^{2}$. Find the number of seconds before the object hits the ground.
A) $0.5 \mathrm{sec}$
B) $0 \mathrm{sec}$
C) $1 \mathrm{sec}$
D) $8 \mathrm{sec}$

Question

Quizplus · Accepted Answer

To find when the object hits the ground, set $h = 0$ and solve for $t$: $0 = 16t - 16t^2$. Factoring out $16t$, we get $16t(1 - t) = 0$, which gives $t = 0$ or $t = 1$. Since $t = 0$ represents the initial launch time, $t = 1$ sec is the time it takes for the object to hit the ground.

Solve the Problem 16ft/sec16 \mathrm{ft} / \mathrm{sec}16ft/sec , Its Height After t\mathrm{t}t

Solve the Problem $16 \mathrm{ft} / \mathrm{sec}$ , Its Height After $\mathrm{t}$