Solve by factoring and using the principle of zero products.
-$15 y^{2}+16 y+4=0$
A) $-\frac{2}{15},-\frac{1}{2}$
B) $-\frac{2}{5},-\frac{2}{3}$
C) $\frac{2}{5},-\frac{2}{3}$
D) $\frac{2}{5}, \frac{2}{3}$

Question

Quizplus · Accepted Answer

The quadratic equation $15y^2 + 16y + 4 = 0$ can be factored as $(5y + 2)(3y + 2) = 0$. Setting each factor to zero gives the solutions $y = -\frac{2}{5}$ and $y = -\frac{2}{3}$.

Solve by Factoring and Using the Principle of Zero Products 15y2+16y+4=015 y^{2}+16 y+4=015y2+16y+4=0

Solve by Factoring and Using the Principle of Zero Products $15 y^{2}+16 y+4=0$