Factor completely.
-$64 \mathrm{x}-25 \mathrm{x}^{3}$
A) $x(8+5 x)^{2}$
B) prime
C) $x(8-5 x)(8-5 x)$
D) $x(8+5 x)(8-5 x)$

Question

Quizplus · Accepted Answer

This expression can be factored by first factoring out the greatest common factor (GCF), which is $x$, giving us $x(64-25x^2)$. Then, recognizing that $64-25x^2$ is a difference of squares, we can factor it further into $(8)^2-(5x)^2$, which gives us $x(8+5x)(8-5x)$.

Factor Completely 64x−25x364 \mathrm{x}-25 \mathrm{x}^{3}64x−25x3 A) x(8+5x)2x(8+5 x)^{2}x(8+5x)2 B) Prime C) x(8−5x)(8−5x)x(8-5 x)(8-5 x)x(8−5x)(8−5x)

Factor Completely $64 \mathrm{x}-25 \mathrm{x}^{3}$ A) $x(8+5 x)^{2}$ B) Prime
C) $x(8-5 x)(8-5 x)$