Factor.
-$x^{2}+\frac{6}{7} x+\frac{9}{49}$
A) $\left(x^{2}+\frac{3}{7}\right)^{2}$
B) $\left(x+\frac{3}{7}\right)\left(x+\frac{3}{7} x\right)$
C) $\left(x+\frac{6}{7}\right)\left(x+\frac{3}{7}\right)$
D) $\left(x+\frac{3}{7}\right)^{2}$

Question

Quizplus · Accepted Answer

The given expression is a perfect square trinomial, factoring to $\left(x+\frac{3}{7}\right)^{2}$ because $\left(\frac{3}{7}\right)^2 = \frac{9}{49}$ and $2 \cdot x \cdot \frac{3}{7} = \frac{6}{7}x$.