Factor by grouping.
-$x^{3}+2 x^{2}-6 x-12$
A) $\left(x^{2}+2\right)(x-6)$
B) $(x-2)\left(x^{2}-6\right)$
C) $(x+2)\left(x^{3}-6 x\right)$
D) $(x+2)\left(x^{2}-6\right)$

Question

Quizplus · Accepted Answer

To factor by grouping, group the terms as $(x^3 + 2x^2) - (6x + 12)$. Factor out $x^2$ from the first group and $-6$ from the second group: $x^2(x + 2) - 6(x + 2)$. Factor out the common factor $(x + 2)$: $(x + 2)(x^2 - 6)$.

Factor by Grouping x3+2x2−6x−12x^{3}+2 x^{2}-6 x-12x3+2x2−6x−12 A) (x2+2)(x−6)\left(x^{2}+2\right)(x-6)(x2+2)(x−6) B) (x−2)(x2−6)(x-2)\left(x^{2}-6\right)(x−2)(x2−6) C) (x+2)(x3−6x)(x+2)\left(x^{3}-6 x\right)(x+2)(x3−6x) D) (x+2)(x2−6)(x+2)\left(x^{2}-6\right)(x+2)(x2−6)

Factor by Grouping $x^{3}+2 x^{2}-6 x-12$ A) $\left(x^{2}+2\right)(x-6)$ B) $(x-2)\left(x^{2}-6\right)$ C) $(x+2)\left(x^{3}-6 x\right)$ D) $(x+2)\left(x^{2}-6\right)$