Solve the Problem $\mathrm{h}+\mathrm{vt}-4.9 \mathrm{t}^{2}$ , Where $\mathrm{h}$ Is the Height in Meters from Which the Launch Occurs

Solve the problem.
-An object's altitude, in meters, is given by the polynomial $\mathrm{h}+\mathrm{vt}-4.9 \mathrm{t}^{2}$ , where $\mathrm{h}$ is the height in meters from which the launch occurs, $\mathrm{v}$ is the initial upward speed in meters per second, and $t$ is the number of seconds for which the rocket is airborne. A pebble is shot upward from the top of a building 191 meters tall. If the initial speed is 35 meters per second, how high above the ground will the pebble be after 2 seconds? Round results to the nearest tenth of a meter.

A) 397.4 meters
B) 280.6 meters
C) 251.2 meters
D) 241.4 meters