Solve the problem.
-In order for a chemical reaction to remain stable, its Celsius temperature must be no more than $137.94^{\circ} \mathrm{C}$. Find the Farenheit temperatures at which the reaction will remain stable. $\left(\mathrm{F}=\frac{9}{5} \mathrm{C}+32\right)$
A) $\mathrm{F} \geq 280.29^{\circ}$
B) $\mathrm{F} \geq 58.86^{\circ}$
C) $\mathrm{F} \leq 58.86^{\circ}$
D) $\mathrm{F} \leq 280.29^{\circ}$

Question

Quizplus · Accepted Answer

To find the Fahrenheit temperature equivalent to $137.94^{\circ}C$, use the conversion formula $F = \frac{9}{5}C + 32$. Substituting $137.94$ for $C$, we get $F = \frac{9}{5} \times 137.94 + 32 = 280.292 + 32 = 280.292^{\circ}F$. Since the reaction must be no more than $137.94^{\circ}C$, the equivalent Fahrenheit temperature must be less than or equal to $280.29^{\circ}F$.

Solve the Problem 137.94∘C137.94^{\circ} \mathrm{C}137.94∘C Find the Farenheit Temperatures at Which the Reaction Will

Solve the Problem $137.94^{\circ} \mathrm{C}$ Find the Farenheit Temperatures at Which the Reaction Will