Solve.
-A 243-foot rope is cut into three pieces. The second piece is twice as long as the first. The third piece is 3 times as long as the second. How long is each piece of rope?
A) First: $30 \mathrm{ft}$; second: $61 \mathrm{ft}$; third: $152 \mathrm{ft}$
B) First: $41 \mathrm{ft}$; second: $81 \mathrm{ft}$; third: $243 \mathrm{ft}$
C) First: $27 \mathrm{ft}$; second: $54 \mathrm{ft}$; thind: $162 \mathrm{ft}$
D) First: $30 \mathrm{ft}$; second: $61 \mathrm{ft}$; third: $182 \mathrm{ft}$

Question

Quizplus · Accepted Answer

Let the length of the first piece be $x$. The second piece is $2x$ and the third piece is $3(2x) = 6x$. The total length is $x + 2x + 6x = 9x = 243$. Solving for $x$ gives $x = 27$, so the pieces are $27 \mathrm{ft}$, $54 \mathrm{ft}$, and $162 \mathrm{ft}$.

Solve -A 243-Foot Rope Is Cut into Three Pieces 30ft30 \mathrm{ft}30ft

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-A 243-Foot Rope Is Cut into Three Pieces $30 \mathrm{ft}$