Consider this initial value problem:

What is the solution of this initial value problem?
A) $ y=\frac{14}{9} e^{-\frac{9}{2} t}+2 e^{\frac{9}{2} t} $
B) $ y=\frac{22}{9} e^{-\frac{9}{2} t}-14 e^{-\frac{9}{2} t} $
C) $ y=e^{\frac{9}{2} t}(2-14 t) $
D) $ y=e^{-\frac{9}{2} t}(2+4 t) $

Question

Consider this initial value problem:

What is the solution of this initial value problem?
A) $ y=\frac{14}{9} e^{-\frac{9}{2} t}+2 e^{\frac{9}{2} t} $ 
B) $ y=\frac{22}{9} e^{-\frac{9}{2} t}-14 e^{-\frac{9}{2} t} $ 
C) $ y=e^{\frac{9}{2} t}(2-14 t) $ 
D) $ y=e^{-\frac{9}{2} t}(2+4 t) $

Quizplus · Accepted Answer

The Answer of Consider this initial value problem:

What is the solution of this initial value problem?
A) $ y=\frac{14}{9} e^{-\frac{9}{2} t}+2 e^{\frac{9}{2} t} $ 
B) $ y=\frac{22}{9} e^{-\frac{9}{2} t}-14 e^{-\frac{9}{2} t} $ 
C) $ y=e^{\frac{9}{2} t}(2-14 t) $ 
D) $ y=e^{-\frac{9}{2} t}(2+4 t) $

Consider This Initial Value Problem: What Is the Solution y=149e−92t+2e92t y=\frac{14}{9} e^{-\frac{9}{2} t}+2 e^{\frac{9}{2} t} y=914​e−29​t+2e29​t

Consider This Initial Value Problem:

What Is the Solution $y=\frac{14}{9} e^{-\frac{9}{2} t}+2 e^{\frac{9}{2} t}$