Consider the Initial Value Problem This Question Is Related

Consider the initial value problem This question is related to using the predictor-corrector method to estimate the solution y(0.2) using a step size of h = 0.05.
For this problem, you will need these values to carry out the computations:

Which of the following show a portion of the formula for the corrected value of

A) $y_{3}+\frac{9 \times 0.05}{24}\left(0.2 \times 2+5 \times\left(y_{3}+\frac{0.05}{24}\left[55\left(2 \times 0.15+5 y_{3}\right) -59\left(2 \times 0.10+5 y_{2}\right) +37\left(2 \times 0.05+5 y_{1}\right) -9 \times 5\right]\right) \right)$
B) $y_{3}-\frac{9 \times 0.05}{24}\left(0.2 \times 2+5 \times\left(y_{3}+\frac{0.05}{24}\left[55\left(2 \times 0.15+5 y_{3}\right) -59\left(2 \times 0.10+5 y_{2}\right) +37\left(2 \times 0.05+5 y_{1}\right) -9 \times 5\right]\right) \right)$
C) $y_{3}+\frac{37 \times 0.05}{24}\left(5 \times\left(y_{3}+\frac{0.05}{24}\left[55\left(2 \times 0.15+5 y_{3}\right) -59\left(2 \times 0.10+5 y_{2}\right) +37\left(2 \times 0.05+5 y_{1}\right) -9 \times 5\right]\right) \right)$
D) $y_{3}-\frac{37 \times 0.05}{24}\left(5 \times\left(y_{3}+\frac{0.05}{24}\left[55\left(2 \times 0.15+5 y_{3}\right) -59\left(2 \times 0.10+5 y_{2}\right) +37\left(2 \times 0.05+5 y_{1}\right) -9 \times 57\right]\right) \right.$