Match each equation on the left with the appropriate description of its graph on the right.
-$(x-3)^{2}+(y+1)^{2}=16$
A) Ellipse; center $(3,1)$
B) Hyperbola; center $(3,1)$
C) Circle; center $(3,-1)$; radius 4
D) Parabola; opens downward
E) Circle; center $(-3,1)$; radius 4
F) Parabola; opens left

Question

Quizplus · Accepted Answer

The equation $(x-3)^{2}+(y+1)^{2}=16$ represents a circle with a center at $(3,-1)$ and a radius of 4, because it is in the standard form of a circle's equation, $(x-h)^2 + (y-k)^2 = r^2$, where $(h,k)$ is the center and $r$ is the radius.

Match Each Equation on the Left with the Appropriate Description (x−3)2+(y+1)2=16(x-3)^{2}+(y+1)^{2}=16(x−3)2+(y+1)2=16

Match Each Equation on the Left with the Appropriate Description $(x-3)^{2}+(y+1)^{2}=16$