The concession stand at a sporting event can fill at most 9 orders per minute. If people arrive randomly at an average rate of $x$ people per minute, then the average wait $W$ in minutes before an order is filled is approximated by $W(x)=\frac{1}{9-x}$, where $0 \leq x

Question

The concession stand at a sporting event can fill at most 9 orders per minute. If people arrive randomly at an average rate of $x$ people per minute, then the average wait $W$ in minutes before an order is filled is approximated by $W(x)=\frac{1}{9-x}$, where $0 \leq x<9$.
(a) Evaluate $W(6), W(8)$, and $W(8.9)$. Interpret the results.
(b) Graph $W$ using the window $[0,9]$ by $[-.5,1]$. Identify the vertical asymptote. What happens to $W$ as $x$ approaches 9 ?
(c) Find $x$ when the wait is 2 minutes.

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The Answer of The concession stand at a sporting event can fill at most 9 orders per minute. If people arrive randomly at an average rate of $x$ people per minute, then the average wait $W$ in minutes before an order is filled is approximated by $W(x)=\frac{1}{9-x}$, where $0 \leq x<9$.
(a) Evaluate $W(6), W(8)$, and $W(8.9)$. Interpret the results.
(b) Graph $W$ using the window $[0,9]$ by $[-.5,1]$. Identify the vertical asymptote. What happens to $W$ as $x$ approaches 9 ?
(c) Find $x$ when the wait is 2 minutes.

The Concession Stand at a Sporting Event Can Fill at Most