Solve the problem.
-How many liters of a 20% alcohol solution must be mixed with 40 liters of a 80% solution to get a 40% solution?
A) 8 L
B) 80 L
C) 12 L
D) 120 L

Name: Solve the problem. -How many liters of a 20% alcohol solution must be mixed with 40 liters of a 80% solution to get a 40% solution? A) 8 L B) 80 L C) 12 L D) 120 L
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Question

Quizplus · Accepted Answer

To solve this, let x be the amount of 20% solution needed. The equation is 0.20x + 0.80(40) = 0.40(x + 40). Solving gives x = 80.

Solve the Problem. -How Many Liters of a 20% Alcohol Solution Must Be