Solve the problem.
-The product of two consecutive integers is 8 less than 8 times their sum. Find the integers.
A) 0, 1
B) 0, 1 or 16, 17
C) 15, 16
D) 0, 1 or 15, 16

Question

Quizplus · Accepted Answer

Let the two consecutive integers be $x$ and $x+1$. The equation based on the given information is $x(x + 1) = 8(x + x + 1) - 8$. Simplifying gives $x^2 + x = 16x + 8 - 8$, which simplifies further to $x^2 - 15x = 0$. Factoring out $x$, we get $x(x - 15) = 0$, which gives the solutions $x = 0$ and $x = 15$. Therefore, the pairs of integers are $0, 1$ and $15, 16$.

Solve the Problem. -The Product of Two Consecutive Integers Is 8 Less Than