A $4.00 \mathrm{~kg}$ object is moving at $5.00 \mathrm{~m} / \mathrm{s}$ NORTH. It strikes a $6.00 \mathrm{~kg}$ object that is moving WEST at 2.00 $\mathrm{m} / \mathrm{s}$. The objects undergo a perfectly inelastic collision (stick together). The velocity of the $4.00 \mathrm{~kg}$ object after the collision is
A) $1.93 \mathrm{~m} / \mathrm{s}$ at an angle of 45.0 degrees NORTH of WEST.
B) $1.93 \mathrm{~m} / \mathrm{s}$ at an angle of 59.0 degrees NORTH of WEST.
C) $2.54 \mathrm{~m} / \mathrm{s}$ at an angle of 35.0 degrees NORTH of WEST.
D) $2.33 \mathrm{~m} / \mathrm{s}$ at an angle of 45.0 degrees NORTH of WEST.
E) $2.33 \mathrm{~m} / \mathrm{s}$ at an angle of 59.0 degrees NORTH of WEST.

Question

Quizplus · Accepted Answer

In a perfectly inelastic collision, momentum is conserved. Calculate the final velocity using the conservation of momentum in both the x (west) and y (north) directions. The final velocity magnitude is $2.33 \mathrm{~m/s}$ and the angle is $59.0$ degrees north of west.

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A $4.00 \mathrm{~kg}$ Object Is Moving At $5.00 \mathrm{~m} / \mathrm{s}$ NORTH It Strikes A Is