A boy with a mass of $55 \mathrm{~kg}$ walks into a room and sees a girl $8.0 \mathrm{~m}$ in front of him who has a mass of $40 \mathrm{~kg}$. What is his gravitational attraction to her?
A) $2.0 \times 10^{8} \mathrm{~N}$
B) $2.1 \times 10^{9} \mathrm{~N}$
C) $2.3 \times 10^{-9} \mathrm{~N}$
D) $2.4 \times 10-8 \mathrm{~N}$
E) $2.2 \times 10-11 \mathrm{~N}$

Question

Quizplus · Accepted Answer

The gravitational force between two masses can be calculated using Newton's law of universal gravitation: $F = G \frac{m_1 m_2}{r^2}$, where $G = 6.674 \times 10^{-11} \, \text{Nm}^2/\text{kg}^2$, $m_1 = 55 \, \text{kg}$, $m_2 = 40 \, \text{kg}$, and $r = 8.0 \, \text{m}$. Plugging these values into the formula gives $F = 6.674 \times 10^{-11} \times \frac{55 \times 40}{8.0^2} = 2.3 \times 10^{-9} \, \text{N}$.

A Boy with a Mass Of 55 kg55 \mathrm{~kg}55 kg Walks into a Room and Sees a Girl

A Boy with a Mass Of $55 \mathrm{~kg}$ Walks into a Room and Sees a Girl