A $1.0 \mathrm{~kg}$ mass is connected to a spring with a spring constant of $9.00 \mathrm{~N} / \mathrm{m}$. If the initial velocity is $0.0 \mathrm{~cm} / \mathrm{s}$ and the initial displacement is $2.0 \mathrm{~cm}$, then what is the maximum kinetic energy of the mass?
A) $0.014 \mathrm{~J}$
B) $0.0018 \mathrm{~J}$
C) $0.0075 \mathrm{~J}$
D) $0.0012 \mathrm{~J}$
E) $0.0090 \mathrm{~J}$

Question

Quizplus · Accepted Answer

The maximum kinetic energy is equal to the maximum potential energy stored in the spring, which is $\frac{1}{2} k x^2$. Here, $k = 9.00 \, \mathrm{N/m}$ and $x = 0.02 \, \mathrm{m}$. So, the maximum kinetic energy is $\frac{1}{2} \times 9.00 \times (0.02)^2 = 0.0018 \, \mathrm{J}$.

A 1.0 kg1.0 \mathrm{~kg}1.0 kg Mass Is Connected to a Spring with a Spring Constant

A $1.0 \mathrm{~kg}$ Mass Is Connected to a Spring with a Spring Constant