A ball is subjected to a pressure of 2.0 atmospheres. The original diameter of the ball is $10.0 \mathrm{~cm}$. The squeezed diameter of the ball is $9.999 \mathrm{~cm}$. The volume strain of the ball is
A) $3.50 \times 10^{-4}$.
B) $3.00 \times 10^{-4}$.
C) $3.30 \times 10^{-4}$.
D) $3.90 \times 10^{-4}$.
E) $3.70 \times 10-4$.

Question

Quizplus · Accepted Answer

The volume strain is calculated using the formula for volume change: $\Delta V/V = 3 \Delta r/r$. Here, $\Delta r = 0.001 \, \text{cm}$ and $r = 5.0 \, \text{cm}$. Thus, volume strain = $3 \times (0.001/5) = 3.00 \times 10^{-4}$.

A Ball Is Subjected to a Pressure of 2 10.0 cm10.0 \mathrm{~cm}10.0 cm

A Ball Is Subjected to a Pressure of 2 $10.0 \mathrm{~cm}$