To be dimensionally consistent, distance $[\mathrm{L}]$, acceleration $\left[\mathrm{L} / \mathrm{T}^{2}\right]$, and time $[\mathrm{T}]$ must be related as follows.
A) distance $=$ acceleration $2 \times$ time
B) distance $=$ acceleration $^{2} \times$ time $^{2}$
C) distance $=$ acceleration $\times$ time
D) distance $=$ acceleration $\times$ time $^{2}$

Question

Quizplus · Accepted Answer

The correct relationship that ensures dimensional consistency between distance, acceleration, and time is given by the equation $distance = acceleration \times time^2$. This is because the units of acceleration ($\mathrm{L/T^2}$) multiplied by the square of time ($\mathrm{T^2}$) give the units of distance ($\mathrm{L}$).

To Be Dimensionally Consistent, Distance [L][\mathrm{L}][L] , Acceleration [L/T2]\left[\mathrm{L} / \mathrm{T}^{2}\right][L/T2] , and Time

To Be Dimensionally Consistent, Distance $[\mathrm{L}]$ , Acceleration $\left[\mathrm{L} / \mathrm{T}^{2}\right]$ , and Time