A proton of mass M rotates with an angular speed of 2 × 10⁶ rad/s in a circle of radius 0.80 m in a cyclotron. What is the orbital angular momentum of the proton? (M = 1.67 × 10^-27 kg) A) 2.1 × 10^-2¹ N-m-s B) 5.3 × 10^-2¹ N-m-s C) 3.9 × 10^-2¹ N-m-s D) 2.9 × 10^-2¹ N-m-s E) 1.1 × 10^-2⁰ N-m-s

Question

Quizplus · Accepted Answer

The orbital angular momentum of the proton is given by L = mvr, where m is the mass of the proton, v is its speed, and r is the radius of the circle. Substituting the given values, we get L = (1.67 × 10^-27 kg)(2 × 10^6 rad/s)(0.80 m) = 2.1 × 10^-21 N-m-s.

A Proton of Mass M Rotates with an Angular Speed