Solve the problem.
-A bullet is fired with a muzzle velocity of 1159 ft/sec from a gun aimed at an angle of 29° above the horizontal. Find the horizontal component of the velocity.
A) 1014 ft/sec
B) -867.0 ft/sec
C) 561.9 ft/sec
D) 642.4 ft/sec

Question

Quizplus · Accepted Answer

The horizontal component of the velocity can be found using the formula $v_x = v \cos(\theta)$, where $v$ is the muzzle velocity and $\theta$ is the angle. Here, $v = 1159$ ft/sec and $\theta = 29^\circ$. Thus, $v_x = 1159 \cos(29^\circ) \approx 1014$ ft/sec.

Solve the Problem. -A Bullet Is Fired with a Muzzle Velocity of 1159