Solve the problem.
-A spring on a horizontal surface can be stretched and held 0.5 m from its equilibrium position with a force of 45 N. How much work is done in compressing the spring 2.5 m from its equilibrium position?
A) 112.5 J
B) 56.25 J
C) 562.5 J
D) 281.25 J

Question

Solve the problem.   
-A spring on a horizontal surface can be stretched and held 0.5 m from its equilibrium position with a force of 45 N. How much work is done in compressing the spring 2.5 m from its equilibrium position?
A) 112.5 J
B) 56.25 J
C) 562.5 J
D) 281.25 J

Quizplus · Accepted Answer

The work done on a spring is given by the formula W = (1/2)kx^2, where k is the spring constant and x is the displacement. First, find k using F = kx: 45 N = k(0.5 m), so k = 90 N/m. Then, calculate the work for 2.5 m: W = (1/2)(90 N/m)(2.5 m)^2 = 281.25 J.

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