Using the equation $T=-\frac{1}{\lambda} \ln (\cdot R N)$ large random numbers produce small time values.

Question

Quizplus · Accepted Answer

In the equation $T=-\frac{1}{\lambda} \ln (\cdot R N)$, assuming $R N$ represents a random number and $\lambda$ is a positive constant, as the random number $R N$ increases, the natural logarithm of $R N$ also increases, which when multiplied by $-\frac{1}{\lambda}$ results in a more negative value, thus not producing smaller but larger negative time values. However, if interpreting "small" as "closer to zero," the statement could be misleading without specifying the context of "small" in terms of absolute value or numerical order on the number line.

Using the Equation T=−1λln⁡(⋅RN)T=-\frac{1}{\lambda} \ln (\cdot R N)T=−λ1​ln(⋅RN) Large Random Numbers Produce Small Time Values

Using the Equation $T=-\frac{1}{\lambda} \ln (\cdot R N)$ Large Random Numbers Produce Small Time Values