When we view video on a computer, analog video is digitized and stored in the frame buffer of the video "frame grabber" card.
Suppose that the video is digitized at NTSC frame rate, has resolution $640 \times 480$ pixels, and is stored with a bit depth of 24 bits.
We're interested in displaying the captured video.
(a) What must be the minimal data rate of the system bus when data is moved from the video frame grabber to the memory for video display?
(b) How much storage capacity is required to store 1 minute of this video?

Question

When we view video on a computer, analog video is digitized and stored in the frame buffer of the video "frame grabber" card. 
Suppose that the video is digitized at NTSC frame rate, has resolution $640 \times 480$ pixels, and is stored with a bit depth of 24 bits.
We're interested in displaying the captured video.
(a) What must be the minimal data rate of the system bus when data is moved from the video frame grabber to the memory for video display?
 (b) How much storage capacity is required to store 1 minute of this video?

Quizplus · Accepted Answer

The Answer is (a) Minimal Data Rate

=640

x 480 pixels/frame

imes 24

bits/pixels

imes 30

frames

/ \mathrm{sec}=210.93 \mathrm{Mbps}

(b)

210.93 \mathrm{Mbps} imes 60 \mathrm{sec}=1.545 \mathrm{~GB}

When We View Video on a Computer, Analog Video Is 640×480640 \times 480640×480

When We View Video on a Computer, Analog Video Is $640 \times 480$