Find the displacement of a simple harmonic wave of amplitude 6.44 m at t = 0.71 s. Assume that the wave number is 2.34 m^-1, the angular frequency is 2.88 rad/s, and that the wave is propagating in the +x direction at x = 1.21 m. A) 4.55 m B) 1.05 m C) 3.54 m D) 2.25 m

Question

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The displacement of a simple harmonic wave is given by the equation: y(x, t) = A * cos(kx - ωt). Substituting the given values: A = 6.44 m, k = 2.34 m^-1, ω = 2.88 rad/s, x = 1.21 m, and t = 0.71 s, we find y(1.21, 0.71) = 6.44 * cos(2.34 * 1.21 - 2.88 * 0.71) ≈ 4.55 m.

Find the Displacement of a Simple Harmonic Wave of Amplitude