Solved

Solve the Initial Value Problem + 2

Question 122

Multiple Choice

Solve the initial value problem Solve the initial value problem + 2 + 2y = 0; y(0) = 4, (0) = -2. A) y(t) = 4 cos t - 6 sin t B) y(t) = 4 cos t - 2 sin t C) y(t) = 4 cos t + 2 sin t D) y(t) = 4 cos t + 6 sin t E) y(t) = 4 cos t + 2 sin t + 2 Solve the initial value problem + 2 + 2y = 0; y(0) = 4, (0) = -2. A) y(t) = 4 cos t - 6 sin t B) y(t) = 4 cos t - 2 sin t C) y(t) = 4 cos t + 2 sin t D) y(t) = 4 cos t + 6 sin t E) y(t) = 4 cos t + 2 sin t + 2y = 0; y(0) = 4, Solve the initial value problem + 2 + 2y = 0; y(0) = 4, (0) = -2. A) y(t) = 4 cos t - 6 sin t B) y(t) = 4 cos t - 2 sin t C) y(t) = 4 cos t + 2 sin t D) y(t) = 4 cos t + 6 sin t E) y(t) = 4 cos t + 2 sin t (0) = -2.


A) y(t) = 4 Solve the initial value problem + 2 + 2y = 0; y(0) = 4, (0) = -2. A) y(t) = 4 cos t - 6 sin t B) y(t) = 4 cos t - 2 sin t C) y(t) = 4 cos t + 2 sin t D) y(t) = 4 cos t + 6 sin t E) y(t) = 4 cos t + 2 sin t cos t - 6 Solve the initial value problem + 2 + 2y = 0; y(0) = 4, (0) = -2. A) y(t) = 4 cos t - 6 sin t B) y(t) = 4 cos t - 2 sin t C) y(t) = 4 cos t + 2 sin t D) y(t) = 4 cos t + 6 sin t E) y(t) = 4 cos t + 2 sin t sin t
B) y(t) = 4 Solve the initial value problem + 2 + 2y = 0; y(0) = 4, (0) = -2. A) y(t) = 4 cos t - 6 sin t B) y(t) = 4 cos t - 2 sin t C) y(t) = 4 cos t + 2 sin t D) y(t) = 4 cos t + 6 sin t E) y(t) = 4 cos t + 2 sin t cos t - 2 Solve the initial value problem + 2 + 2y = 0; y(0) = 4, (0) = -2. A) y(t) = 4 cos t - 6 sin t B) y(t) = 4 cos t - 2 sin t C) y(t) = 4 cos t + 2 sin t D) y(t) = 4 cos t + 6 sin t E) y(t) = 4 cos t + 2 sin t sin t
C) y(t) = 4 Solve the initial value problem + 2 + 2y = 0; y(0) = 4, (0) = -2. A) y(t) = 4 cos t - 6 sin t B) y(t) = 4 cos t - 2 sin t C) y(t) = 4 cos t + 2 sin t D) y(t) = 4 cos t + 6 sin t E) y(t) = 4 cos t + 2 sin t cos t + 2 Solve the initial value problem + 2 + 2y = 0; y(0) = 4, (0) = -2. A) y(t) = 4 cos t - 6 sin t B) y(t) = 4 cos t - 2 sin t C) y(t) = 4 cos t + 2 sin t D) y(t) = 4 cos t + 6 sin t E) y(t) = 4 cos t + 2 sin t sin t
D) y(t) = 4 Solve the initial value problem + 2 + 2y = 0; y(0) = 4, (0) = -2. A) y(t) = 4 cos t - 6 sin t B) y(t) = 4 cos t - 2 sin t C) y(t) = 4 cos t + 2 sin t D) y(t) = 4 cos t + 6 sin t E) y(t) = 4 cos t + 2 sin t cos t + 6 Solve the initial value problem + 2 + 2y = 0; y(0) = 4, (0) = -2. A) y(t) = 4 cos t - 6 sin t B) y(t) = 4 cos t - 2 sin t C) y(t) = 4 cos t + 2 sin t D) y(t) = 4 cos t + 6 sin t E) y(t) = 4 cos t + 2 sin t sin t
E) y(t) = 4 Solve the initial value problem + 2 + 2y = 0; y(0) = 4, (0) = -2. A) y(t) = 4 cos t - 6 sin t B) y(t) = 4 cos t - 2 sin t C) y(t) = 4 cos t + 2 sin t D) y(t) = 4 cos t + 6 sin t E) y(t) = 4 cos t + 2 sin t cos t + 2 Solve the initial value problem + 2 + 2y = 0; y(0) = 4, (0) = -2. A) y(t) = 4 cos t - 6 sin t B) y(t) = 4 cos t - 2 sin t C) y(t) = 4 cos t + 2 sin t D) y(t) = 4 cos t + 6 sin t E) y(t) = 4 cos t + 2 sin t sin t

Correct Answer:

verifed

Verified

Unlock this answer now
Get Access to more Verified Answers free of charge

Related Questions

Q117: Find the general solution of the differential

Q118: Find the general solution of the differential

Q119: Find the general solution of the differential

Q120: Find the general solution of the differential

Q121: Solve the initial value problem 12

Q123: Solve the initial value problem

Q124: Solve the initial value problem

Q125: Find a homogeneous linear second-order differential equation

Q126: Find a homogeneous linear second-order differential equation

Q127: Determine the period and circular frequency of

Unlock this Answer For Free Now!

View this answer and more for free by performing one of the following actions

qr-code

Scan the QR code to install the App and get 2 free unlocks

upload documents

Unlock quizzes for free by uploading documents